\(PTHH:2H_2O\rightarrow2H_2+O_2\)
Ta có:
\(n_{H2O}=\frac{1,8}{18}=0,1\left(mol\right)\)
\(n_{H2}=n_{H2O}=0,1\left(mol\right)\)
\(\Rightarrow n_{O2}=\frac{0,1}{2}=0,05\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}V_{H2}=\frac{0,1}{0,15}.100\%=66,67\%\\\%V_{O2}=100\%-66,67\%=33,33\%\end{matrix}\right.\)