a,PTHH : \(2Al+3H_2SO_4->Al_2\left(SO_4\right)_3+3H_2\) (1)
\(H_2+CuO->Cu+H_2O\) (2)
b, \(n_{Cu}=\frac{0,64}{64}=0,01\left(mol\right)\)
Theo (2) : \(n_{H_2}=n_{Cu}=0,01\left(mol\right)\)
Theo (1) : \(n_{H_2SO_4}=n_{H_2}=0,01\left(mol\right)\)
=> \(m_{H_2SO_4}=0,01.98=0,98\left(g\right)\)
Chúc bạn học tốt :>