\( \left| {2x - 1} \right| = \left| {2x + 3} \right|\\ \Leftrightarrow \left[ \begin{array}{l} 2x - 1 = 2x + 3\\ 2x - 1 = - \left( {2x + 3} \right) \end{array} \right. \Leftrightarrow \left[ \begin{array}{l} 2x - 2x = 3 + 1\\ 2x - 1 = - 2x - 3 \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l} 0x = 4\left( {VN} \right)\\ 2x + 2x = - 3 + 1 \end{array} \right. \Leftrightarrow 4x = - 2 \Leftrightarrow x = - \dfrac{1}{2} \)
Vậy \(x=-\dfrac{1}{2}\)