Lời giải:
Ta có:
\(\cos (\overrightarrow{a}, \overrightarrow{b})=\frac{\overrightarrow{a}.\overrightarrow{b}}{|\overrightarrow{a}||\overrightarrow{b}|}=\frac{2.6+(-3).4}{\sqrt{2^2+(-3)^2}.\sqrt{6^2+4^2}}\)
\(=0\)
\(\Rightarrow \angle (\overrightarrow{a}; \overrightarrow{b})=\frac{\pi}{2}\)