\(\dfrac{63}{8}+5\dfrac{1}{2}\)
\(=\dfrac{63}{8}+\dfrac{11}{2}\)
\(=\dfrac{63}{8}+\dfrac{44}{8}\)
\(=\dfrac{107}{8}\)
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Violympic toán 8
Các câu hỏi tương tự
Tính:
\(\dfrac{63}{8}+5\dfrac{2}{2}\)
Tính giá trị A= \(3\dfrac{1}{117}.\dfrac{1}{119}-\dfrac{4}{117}.5\dfrac{118}{119}-\dfrac{5}{117.119}+\dfrac{8}{39}\)
tìm nghiệm của phân thức viết dưới dạng phân số
a.dfrac{4}{left(2+dfrac{2}{1+dfrac{4}{5}}right)x-left(1-dfrac{4}{2+dfrac{1}{1+dfrac{7}{8}}}right)}+dfrac{1}{2+dfrac{1}{3+dfrac{1}{4}}}
4+dfrac{2}{1+dfrac{8}{9}}
b.
dfrac{1}{2+dfrac{3}{4+dfrac{5}{6+dfrac{7}{8}}}}dfrac{1}{3+dfrac{2}{5+dfrac{3}{7+dfrac{4}{9}}}}+x.left(4+dfrac{1}{1+dfrac{1}{1+dfrac{1}{2}}}right)
(giải bằng máy tính casio )
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tìm nghiệm của phân thức viết dưới dạng phân số
a.\(\dfrac{4}{\left(2+\dfrac{2}{1+\dfrac{4}{5}}\right)x-\left(1-\dfrac{4}{2+\dfrac{1}{1+\dfrac{7}{8}}}\right)}+\dfrac{1}{2+\dfrac{1}{3+\dfrac{1}{4}}}\)
= \(4+\dfrac{2}{1+\dfrac{8}{9}}\)
b.
\(\dfrac{1}{2+\dfrac{3}{4+\dfrac{5}{6+\dfrac{7}{8}}}}=\dfrac{1}{3+\dfrac{2}{5+\dfrac{3}{7+\dfrac{4}{9}}}}+x.\left(4+\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{2}}}\right)\)
(giải bằng máy tính casio )
thực hiện phép tính:
1) dfrac{-1}{12}- (2dfrac{5}{8}- dfrac{1}{3})
2) -1,75 - (dfrac{-1}{9} - 2dfrac{1}{18})
3) -dfrac{5}{6} - (-dfrac{3}{8}+dfrac{1}{10})
4) dfrac{2}{5}+(-dfrac{4}{3})+(-dfrac{1}{2})
5) dfrac{3}{12}- (dfrac{6}{15}- dfrac{3}{10})
6) (8dfrac{5}{11}+3dfrac{5}{8})- 3dfrac{5}{11}
7) dfrac{-1}{4}. 13dfrac{9}{11}- 0,25 . 6dfrac{2}{11}
8) dfrac{4}{9}:(-dfrac{1}{7})+ 6dfrac{5}{9}: (-dfrac{1}{7})
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thực hiện phép tính:
1) \(\dfrac{-1}{12}\)- (2\(\dfrac{5}{8}\)- \(\dfrac{1}{3}\))
2) -1,75 - (\(\dfrac{-1}{9}\) - 2\(\dfrac{1}{18}\))
3) -\(\dfrac{5}{6}\) - (\(-\dfrac{3}{8}\)+\(\dfrac{1}{10}\))
4) \(\dfrac{2}{5}\)+(\(-\dfrac{4}{3}\))+(\(-\dfrac{1}{2}\))
5) \(\dfrac{3}{12}\)- (\(\dfrac{6}{15}\)- \(\dfrac{3}{10}\))
6) (\(8\dfrac{5}{11}\)+\(3\dfrac{5}{8}\))- \(3\dfrac{5}{11}\)
7) \(\dfrac{-1}{4}\). \(13\dfrac{9}{11}\)- 0,25 . \(6\dfrac{2}{11}\)
8) \(\dfrac{4}{9}\):(\(-\dfrac{1}{7}\))+ \(6\dfrac{5}{9}\): (\(-\dfrac{1}{7}\))
Giải các phương trình sau:
1. \(a,\dfrac{6}{x-1}-\dfrac{4}{x-3}=\dfrac{8}{2x-6}\)
\(b,\dfrac{1}{x-2}+\dfrac{5}{x+1}=\dfrac{3}{2-x}\)
\(c,\dfrac{3x}{x-2}-\dfrac{x}{x-5}=\dfrac{3x}{\left(x-2\right)\left(5-x\right)}\)
2. \(a,\left(x+2\right)\left(3-4x\right)=x^2+4x+4\)
\(b,2x^2-6x+1\)
4.Giải phương trình
a) dfrac{x+5}{x-5}-dfrac{x-5}{x+5}dfrac{20}{x^2-25}
b)dfrac{1}{x-1}+dfrac{2}{x+1}dfrac{x}{x^2-1}
c)5+dfrac{76}{x^2-16}dfrac{2x-1}{x+4}-dfrac{3x-1}{4-x}
d)dfrac{90}{x}-dfrac{36}{x-6}2
e)dfrac{1}{x}+dfrac{1}{x+10}dfrac{1}{12}
f)dfrac{x+3}{x-3}-dfrac{1}{x}dfrac{3}{xleft(x-3right)}
g)dfrac{3}{x+2}-dfrac{2}{x-2}+dfrac{8}{x^2-4}0
h)dfrac{3}{x+2}-dfrac{2}{x-3}dfrac{8}{left(x-3right)left(x+2right)}
i)dfrac{x}{2x+6}-dfrac{x}{2x+2}dfrac{3x+2}{left(x+1right)left(x+3right)}
k)d...
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4.Giải phương trình
a) \(\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}=\dfrac{20}{x^2-25}\)
b)\(\dfrac{1}{x-1}+\dfrac{2}{x+1}=\dfrac{x}{x^2-1}\)
c)\(5+\dfrac{76}{x^2-16}=\dfrac{2x-1}{x+4}-\dfrac{3x-1}{4-x}\)
d)\(\dfrac{90}{x}-\dfrac{36}{x-6}=2\)
e)\(\dfrac{1}{x}+\dfrac{1}{x+10}=\dfrac{1}{12}\)
f)\(\dfrac{x+3}{x-3}-\dfrac{1}{x}=\dfrac{3}{x\left(x-3\right)}\)
g)\(\dfrac{3}{x+2}-\dfrac{2}{x-2}+\dfrac{8}{x^2-4}=0\)
h)\(\dfrac{3}{x+2}-\dfrac{2}{x-3}=\dfrac{8}{\left(x-3\right)\left(x+2\right)}\)
i)\(\dfrac{x}{2x+6}-\dfrac{x}{2x+2}=\dfrac{3x+2}{\left(x+1\right)\left(x+3\right)}\)
k)\(\dfrac{x}{x+1}-\dfrac{2x-3}{1-x}=\dfrac{3x^2+5}{x^2-1}\)
l)\(\dfrac{5}{x+7}+\dfrac{8}{2x+14}=\dfrac{3}{2}\)
m)\(\dfrac{x-1}{x}-\dfrac{1}{x+1}=\dfrac{2x-1}{x^2+x}\)
Cần gấp ạ
Tính:
\(a,\dfrac{x+3}{2x-1}-\dfrac{x^2-5}{4x^2-4x+1}-\dfrac{2x^3+5x^2-x-1}{8x^3-12x^2+6x-1}\)
\(b,\dfrac{1}{1-x}+\dfrac{1}{1+x}+\dfrac{2}{1+x^2}+\dfrac{4}{1+x^4}+\dfrac{8}{1+x^8}+\dfrac{16}{1+x^{16}}\)
Tính giá trị biểu thức sau và biểu diễn kết quả dưới dạng phân số:
\(9+\dfrac{1}{8+\dfrac{2}{7+\dfrac{3}{6+\dfrac{4}{5+\dfrac{5}{4+\dfrac{6}{3+\dfrac{7}{2+\dfrac{8}{9}}}}}}}}\)
(Giải toán CASIO)
Giải PT sau:a, 3x - 7 0b, 8 - 5x 0c, 3x - 2 5x + 8d, dfrac{3x-2}{3} dfrac{1-x}{2}e, ( 5x + 1)(x - 3) 0f, (x + 1)(2x - 3) 0g, 4x(x + 3) - 5(x + 3) 0h, 8(x - 6) - 2x(6 - x) 0i, dfrac{2}{x-1} + dfrac{1}{x} dfrac{2x+5}{x^2-x}k, dfrac{3}{x+2} - dfrac{2}{x-2} dfrac{2-x}{x^2-4}m, dfrac{3}{x} - dfrac{2}{x-3} dfrac{4-x}{x^2-3}n,dfrac{3}{2x+10}+ dfrac{2x}{x^2-25} dfrac{3}{x-5}u, dfrac{2}{x+3} - dfrac{3}{x-2} dfrac{x+4}{left(x+3right)left(x-2right)}
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Giải PT sau:
a, 3x - 7 = 0
b, 8 - 5x = 0
c, 3x - 2 = 5x + 8
d, \(\dfrac{3x-2}{3}\) = \(\dfrac{1-x}{2}\)
e, ( 5x + 1)(x - 3) = 0
f, (x + 1)(2x - 3) = 0
g, 4x(x + 3) - 5(x + 3) = 0
h, 8(x - 6) - 2x(6 - x) = 0
i, \(\dfrac{2}{x-1}\) + \(\dfrac{1}{x}\) = \(\dfrac{2x+5}{x^2-x}\)
k, \(\dfrac{3}{x+2}\) - \(\dfrac{2}{x-2}\) = \(\dfrac{2-x}{x^2-4}\)
m, \(\dfrac{3}{x}\) - \(\dfrac{2}{x-3}\) = \(\dfrac{4-x}{x^2-3}\)
n,\(\dfrac{3}{2x+10}\)+ \(\dfrac{2x}{x^2-25}\) = \(\dfrac{3}{x-5}\)
u, \(\dfrac{2}{x+3}\) - \(\dfrac{3}{x-2}\) = \(\dfrac{x+4}{\left(x+3\right)\left(x-2\right)}\)