Question

tính:

a) ( \(\frac{3}{7}+\frac{1}{2}\))²

b) ( \(\frac{3}{4}-\frac{5}{6}\))²

c) \(\frac{5^4.20^4}{25^5.4^5}\)

d) ( \(\frac{-10}{3}\) )⁵. (\(\frac{-6}{5}\))⁴

Answer 1

a)\(\left(\frac{3}{7}+\frac{1}{2}\right)^2=\left(\frac{6}{14}+\frac{7}{14}\right)^2=\left(\frac{13}{14}\right)^2=\frac{169}{196}\)

b)\(\left(\frac{3}{4}-\frac{5}{6}\right)^2=\left(\frac{9}{12}-\frac{10}{12}\right)^2=\left(-\frac{1}{12}\right)^2=\frac{1}{144}\)

c)\(\frac{5^4\cdot20^4}{25^5\cdot4^5}=\frac{\left(20\cdot5\right)^4}{\left(25\cdot4\right)^5}=\frac{100^4}{100^5}=\frac{1}{100}\)

d)\(\left(-\frac{10}{3}\right)^5\cdot\left(-\frac{6}{5}\right)^4=\left(-\frac{10}{3}\right)^4\cdot\left(-\frac{10}{3}\right)\cdot\left(-\frac{6}{5}\right)^4=\left[-\frac{10}{3}\cdot\frac{-6}{5}\right]^4\cdot\frac{-10}{3}=4^4\cdot\frac{-10}{3}=256\cdot\frac{-10}{3}=\frac{-2560}{3}\)