Question

Tính số mol của:

a)7,8g Al (OH)3

b)34,2g AL2(SO4)3

c) 3,36l H2 (đktc)

Giúp mình được không? Mình vã quá:<<<

Answer 1

https://i.imgur.com/Y0Phxx7.jpg

Answer 2

a) \(n_{Al\left(OH\right)_3}=\frac{7,8}{78}=0,1mol\)

b) \(n_{Al_2\left(SO_4\right)_3}=\frac{34,2}{342}=0,1mol\)

c) \(n_{H_2}=\frac{3,36}{22,4}=0,15mol\)

Answer 3

https://i.imgur.com/3p1qwi9.jpg

Answer 4

a) n\(_{Al\left(OH\right)3}=\frac{7,8}{78}=0,1\left(mol\right)\)

b) n\(_{Al2\left(SO4\right)3}=\frac{34,2}{342}=0,1\left(mol\right)\)

c) n\(_{H2}=\frac{3,36}{22,4}=0,15\left(mol\right)\)