\(\dfrac{3}{4}+\dfrac{5}{7}=\dfrac{21}{28}+\dfrac{20}{28}=\dfrac{41}{28}\)
\(\dfrac{4}{5}\times\dfrac{5}{7}=\dfrac{4\times5}{5\times7}=\dfrac{20}{35}=\dfrac{4}{7}\)
\(\dfrac{3}{4}+\dfrac{5}{7}=\dfrac{21}{28}+\dfrac{20}{28}=\dfrac{41}{28}\)
\(\dfrac{4}{5}\times\dfrac{5}{7}=\dfrac{4}{7}\)