Question

Tính pH của các dung dịch sau:

a/ \(HCl\) 0,0001M

b/ \(H_2SO_4\) 0,0005M

c/ \(Ba\left(OH\right)_2\) 0,0005M

Answer 1

`a)C_[M_[HCl]]=0,0001(M)=10^[-4](M)`

   `=>[H^+ ]=10^[-4](M)`

  `=>pH=4`

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`b)C_[M_[H_2 SO_4]]=0,0005(M)=5.10^[-4](M)`

    `=>[H^+ ]=2.5.10^[-4]=10^[-3](M)`

  `=>pH=3`

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`c)C_[M_[Ba(OH)_2]]=0,0005(M)=5.10^[-4](M)`

   `=>[OH^- ]=2.5.10^[-4]=10^[-3](M)`

  `=>[H^+ ]=[10^[-14]]/[10^[-3]]=10^[-11](M)`

  `=>pH=11`