\(b,1.2.3...9-1.2.3...8-1.2.3...7.8^2\)
\(=(1.2.3...8).(9-1-8)\)
\(=(1.2.3...8).0\)
\(=0\)
a, 1 + 3 − 5 − 7 + 9 + 11 − ... − 397 − 399
= (1 + 3 - 5 - 7) + (9 + 11 - 13 - 15) + ... + (393 + 395 - 397 - 399)
= (-8) + (-8) + ... + (-8)
= (-8) . 50 (vì có 50 lần số hạng -8)
= - 400
_Vậy 1 + 3 − 5 − 7 + 9 + 11 − ... − 397 − 399 = -400
b, 1 . 2 . 3 ... 9 - 1 . 2 . 3 ... 8 - 1 . 2 . 3 ... 7 . 82
= (1 . 2 . 3 ... 8) (9 - 1 - 8)
= (1 . 2 . 3 ... 8) . 0
= 0
c, 1152 - (374 + 1152) + (-65 + 344)
= 1152 - 374 - 1152 + (-65) + 344
= (1152 - 1152) + [(-374) + 344 + (-65)]
= 0 + [(-3) + (-65)]
= -68