a) \(n_P=\dfrac{46,5}{31}=1,5\left(mol\right)\)
\(4P+5O_2\rightarrow2P_2O_5\)
1,5.....1,875 (mol)
\(\rightarrow m_{O_2}=1,875.32=60\left(g\right)\)
c. \(n_{H_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
\(2H_2+O_2\rightarrow2H_2O\)
0,15.....0,075 (mol)
\(\rightarrow m_{O_2}=0,075.32=2,4\left(g\right)\)
a, \(n_P=\dfrac{m}{M}=1,5\left(mol\right)\)
\(PTHH:4P+5O_2\rightarrow2P_2O_5\)
...............1,5......1,875......
=> \(m_{O_2}=n.M=60\left(g\right)\)
b, \(n_{Al}=\dfrac{m}{M}=2,5\left(mol\right)\)
\(PTHH:4Al+3O_2\rightarrow2Al_2O_3\)
................2,5.....1,875.......
=> \(m_{O_2}=n.M=60\left(g\right)\)
c, ( Chắc là ở ĐKTC )
\(n_{H_2}=\dfrac{V}{22,4}=1,5\left(mol\right)\)
\(PTHH:2H_2+O_2\rightarrow2H_2O\)
...............1,5....0,75...........
=> \(m_{O_2}=n.M=24\left(g\right)\)
\(a\))
\(n_P=\dfrac{46,5}{31}=1,5\left(mol\right)\)
\(4P+5O_2\xrightarrow[]{t^o}2P_2O_5\)
\(1,5\) \(1,875\) \(\left(mol\right)\)
\(m_{O_2}=1,875.32=60\left(g\right)\)
\(b\))
\(n_{Al}=\dfrac{67,5}{27}=2,5\left(mol\right)\)
\(4Al+3O_2\xrightarrow[]{t^o}2Al_2O_3\)
\(2,5\) \(1,875\) \(\left(mol\right)\)
\(m_{O_2}=1,875.32=60\left(g\right)\)
\(c\))Câu này mình đặt ở đktc nhé
\(n_{H_2}=\dfrac{33,6}{22,4}=1,5\left(mol\right)\)
\(2H_2+O_2\xrightarrow[]{t^o}2H_2O\)
\(1,5\) \(0,75\) \(\left(mol\right)\)
\(m_{O_2}=0,75.32=24\left(g\right)\)
