a) nN2 = \(\frac{12,044.10^{23}}{6,022.10^{23}}=2\left(mol\right)\)
\(\Rightarrow m_{N_2}=n.M=2.28=56\left(gam\right)\)
b) nCO2 = \(\frac{1,5.10^{23}}{6,022.10^{23}}\approx0,25\left(mol\right)\)
\(\Rightarrow m_{CO_2}=n.M=0,25.44=11\left(gam\right)\)