Giải:
Ta có: \(\dfrac{a}{b}=\dfrac{3}{4}\Rightarrow\dfrac{a}{3}=\dfrac{b}{4}\)
Đặt \(\dfrac{a}{3}=\dfrac{b}{4}=k\Rightarrow\left\{{}\begin{matrix}a=3k\\b=4k\end{matrix}\right.\)
\(\dfrac{2a-5b}{a-3b}=\dfrac{6k-20k}{3k-12k}=\dfrac{-24k}{-9k}=\dfrac{24}{9}=\dfrac{8}{3}\)
Vậy \(\dfrac{2a-5b}{a-3b}=\dfrac{8}{3}\)