Tìm giá trị của biểu thức :
\(A=-1,6:\left(1+\dfrac{2}{3}\right)\)
\(B=1,4.\dfrac{15}{49}-\left(\dfrac{4}{5}+\dfrac{2}{3}\right):2\dfrac{1}{5}\)
1.Tính nhanh:
A= \(\dfrac{\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}}{\dfrac{5}{12}+1-\dfrac{7}{11}}\)
2. Cho: B =\(\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{6}+...+\dfrac{1}{19}\) .Hãy chứng tỏ rằng B > 1.
3. Rút gọn:
a) C= \(\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right)....\left(1-\dfrac{1}{20}\right)\)
b) D= \(1+\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2012}}\)
4. So sánh: E=\(\dfrac{20^{10}+1}{20^{10}-1}\) và F =\(\dfrac{20^{10}-1}{20^{10}-3}\)
5. Tính giá trị của biểu thức:
M= \(\dfrac{\dfrac{3}{5}+\dfrac{3}{7}-\dfrac{3}{11}}{\dfrac{4}{5}+\dfrac{4}{7}-\dfrac{4}{11}}\)
a) \(\dfrac{2}{1^2}.\dfrac{6}{2^2}.\dfrac{12}{3^2}.\dfrac{20}{4^2}.\dfrac{30}{5^2}.....\dfrac{110}{10^2}.x=-20\)
b) \(\left(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2013}\right).x+2013=\dfrac{2014}{1}+\dfrac{2015}{2}+...+\dfrac{4025}{2012}+\dfrac{4026}{2013}\)
c) \(\left(\dfrac{1}{1.2}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right).x=\dfrac{2012}{51}+\dfrac{2012}{52}+...+\dfrac{2012}{99}+\dfrac{2012}{100}\)
tính H = \(\dfrac{\dfrac{1}{99}+\dfrac{2}{98}+\dfrac{3}{97}+...+\dfrac{98}{2}+\dfrac{99}{1}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{100}}:\dfrac{92-\dfrac{1}{9}-\dfrac{2}{10}-\dfrac{3}{11}-...-\dfrac{92}{100}}{\dfrac{1}{45}+\dfrac{1}{50}+\dfrac{1}{55}+...+\dfrac{1}{500}}\)
Chứng tỏ rằng:
a) \(S=\dfrac{1}{5}+\dfrac{1}{13}+\dfrac{1}{14}+\dfrac{1}{15}+\dfrac{1}{61}+\dfrac{1}{62}+\dfrac{1}{63}< \dfrac{1}{2}\)
b) \(S=\dfrac{1}{41}+\dfrac{1}{42}+...+\dfrac{1}{80}>\dfrac{7}{12}\)
c) \(S=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{20}}< 1\)
d) \(\dfrac{49}{100}< S=\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{99^2}< 1\)
Các bạn giải ra từng bước dùm mik nha
Thanks m.n
Tính
A=1+2+3+4+5+.....+99+100
B= \(\dfrac{1}{2}\)+ \(\dfrac{1}{6}\)+\(\dfrac{1}{12}\)+\(\dfrac{1}{20}\)+ \(\dfrac{1}{30}\)+....+\(\dfrac{1}{9900}\)
Tính giá trị biểu thức
A=\(\dfrac{1}{2.5}\)+\(\dfrac{1}{5.8}\)+\(\dfrac{1}{8.11}\)+.....+\(\dfrac{1}{92.95}\)+\(\dfrac{1}{95.98}\)
Mong mn giúp đỡ
Bài 1: Rút gọn các phân số sau: a/ \(\dfrac{-63}{81}\), b/ \(\dfrac{5.6}{9.35}\), c/ \(\dfrac{7.2+8}{2.14.5}\)
Bài 2: Tìm X: a/ \(\dfrac{4}{7}\)-X = \(\dfrac{1}{2}\). X + \(\dfrac{2}{7}\); b/ X : \(3\dfrac{1}{5}\)= \(1\dfrac{1}{2}\); c/ X . \(\dfrac{3}{4}\)= \(-1\dfrac{5}{8}\)
Bài 3: Tính giá trị biểu thức: A= \(\dfrac{-3}{5}\)+ ( \(\dfrac{-2}{5}\)+ 2 ); B= \(\dfrac{3}{7}\)+ ( -\(\dfrac{1}{5}\) + \(\dfrac{-3}{7}\) ); C= ( -\(\dfrac{5}{24}\) + 0,75 + \(\dfrac{7}{12}\) ) : (-2. \(\dfrac{1}{8}\))
Bài 4: Tìm X: a/ ( \(2\dfrac{1}{3}\) + \(3\dfrac{1}{2}\) ) . X = \(-4\dfrac{1}{6}\) + \(3\dfrac{1}{7}\); b/ X : ( \(3\dfrac{1}{2}\) - \(5\dfrac{1}{6}\) ) = \(4\dfrac{1}{5}\) - \(6\dfrac{2}{3}\)
Các bạn giúp mình nha!
\(G=\dfrac{2}{5.8}+\dfrac{2}{8.11}+...+\dfrac{2}{95.98}+\dfrac{2}{98.101}\)
\(X=\dfrac{2^2}{1.3}.\dfrac{3^2}{2.4}.\dfrac{4^2}{3.5}...\dfrac{99^2}{98.100}\)
\(K=\dfrac{1}{3}.\dfrac{1}{15}.\dfrac{1}{35}...\dfrac{1}{9999}\)