\(\frac{6^8\cdot16^5}{2^{27}\cdot27^3}=\frac{\left(2\cdot3\right)^8\cdot\left(2^4\right)^5}{2^{27}\cdot\left(3^3\right)^3}\)
\(=\frac{2^8\cdot3^8\cdot2^{20}}{2^{27}\cdot3^3}=\frac{2^{28}\cdot3^8}{2^{27}\cdot3^9}=\frac{2}{3}\)
\(\frac{6^8\cdot16^5}{2^{27}\cdot27^3}=\frac{\left(2\cdot3\right)^8\cdot\left(2^4\right)^5}{2^{27}\cdot\left(3^3\right)^3}\)
\(=\frac{2^8\cdot3^8\cdot2^{20}}{2^{27}\cdot3^3}=\frac{2^{28}\cdot3^8}{2^{27}\cdot3^9}=\frac{2}{3}\)
Thực hiện phép tính:
a) \(-\frac{3^4.4^4}{2^2.6^2}\)
b) \(\frac{27^2.8^5}{6^6.32^3}\)
c) \(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}\)
A = \(\frac{\frac{1}{11}-\frac{1}{13}-\frac{1}{17}}{\frac{5}{11}-\frac{5}{13}-\frac{5}{17}}+\frac{\frac{2}{3}-\frac{2}{9}-\frac{2}{27}+\frac{2}{81}}{\frac{7}{3}-\frac{7}{9}-\frac{7}{27}+\frac{7}{81}}\)
B = \(\frac{5^2}{11.16}+\frac{5^2}{16.21}+\frac{5^2}{21.26}+\frac{5^2}{26.31}+...+\frac{5^2}{56.81}\)
C = \(1-\frac{1}{3}-\frac{1}{6}-\frac{1}{10}-\frac{1}{15}-...-\frac{1}{1225}\)
\(a,\left(-3\right)^{x+3}=-\frac{1}{27}\)
\(b,\left(-6\right)^{2x+2}=\frac{1}{36}\)
\(c,\left(-3\right)^{x+5}=\frac{1}{81}\)
\(d,\left(\frac{1}{9}^x\right)=\left(\frac{1}{27}\right)^6\)
\(e,\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)
\(f,5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(r,4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(h,\left(\frac{1}{2}-\frac{1}{3}\right).6x+6^{x+2}=6^{10}+6^7\)
nhờ mấy bn giúp mk tối mình nộp rồi
1) Tính:
a)\(\left(\frac{1}{3}-\frac{1}{5}\right)^2:\left(\frac{1}{5}\right)^2\)
b) \(\frac{2^3.5^2.8}{10^{10}}\)
c) \(7\frac{1}{23}+\frac{10}{27}-5\frac{1}{23}+\frac{17}{27}+2^3\)
d) \(5.\left(-\frac{5}{2}\right)^2+\frac{1}{5}.\left(-3\right)^2\)
CÁC BẠN GIÚP MIK VỚI
tính :
a) \(\frac{4}{9}:\frac{-1}{7}+6\frac{5}{9}:\frac{-1}{7}\)
b) \(\left(2\frac{1}{3}+3\frac{1}{2}\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7\frac{1}{2}\)
c) \(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Tính :
\(B=\frac{7}{4}\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)
\(C=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
1 tính
a)\(\frac{3^6\cdot45^4-15^{13}\cdot5^{-9}}{27^4\cdot25^3+45^6}\)
Thực hiện phép tính:
\(\frac{2^{16}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)