1)\(\left(\sqrt{9}-\sqrt{4}\right)^{\sqrt{4}}+\left(\sqrt{25}-\sqrt{36}\right)^{\sqrt{9}}\)
= (3-2)2 + ( 5-4)3
= 12 + 13
=1 +1
=2
a) (căn 9 - căn 4 ) ^ căn 4 + (căn 25 - căn 36) ^ căn 9
= (3-2)^2 + (5-6)^3 = 0
b) căn (81/25) -1/5 .(-3 + căn 16)^(20) . (-2)^3
=9/5 - 1/5.1.(-8)=17/5
c) [căn ( căn 1) + căn ( căn 16)+căn ( căn 81) +căn ( căn 256)]^ (căn 100- căn 81)
=[ 1+2+ 3+4]1 =10
1. \(\left(\sqrt{9}-\sqrt{4}\right)^{\sqrt{4}}+\left(\sqrt{25}-\sqrt{36}\right)^{\sqrt{9}}\) \(=\left(3-2\right)^2+\left(5-6\right)^3=1^2+\left(-1\right)^3\) \(=1+1=0\) 2.\(\sqrt{\dfrac{81}{25}}-\dfrac{1}{5}\left(-3+\sqrt{16}\right)^{20}\) \(=\dfrac{9}{5}-\dfrac{1}{5}\left(-3+4\right)^{20}=\dfrac{9}{5}-\dfrac{1}{5}.1^{20}\) \(=\dfrac{9}{5}.1=\dfrac{9}{5}\) 3. \(\left(\sqrt{\sqrt{1}}+\sqrt{\sqrt{16}}+\sqrt{\sqrt{81}}+\sqrt{\sqrt{256}}\right)^{\sqrt{100}-\sqrt{81}}\) \(=\left(1+2+3+4\right)^1=10^1=10\)