Question

Tính:

\(15\dfrac{1}{4}:\left(\dfrac{-7}{5}\right)-25\dfrac{1}{4}\cdot\left(\dfrac{-7}{5}\right)\)

38-2y=4/3

y^x-4.x^x+6

\(\left(\dfrac{x}{y}\right)^{\left(4x-9\right)}\)

((2x+y)⁶)⁸

x^2y.x^4z

Answer 1

a) Có lẽ câu này sai đề rồi. Dấu chia phải là dấu nhân chứ?

Mình sửa đề luôn nhé.

\(15\dfrac{1}{4}.\left(-\dfrac{7}{5}\right)-25\dfrac{1}{4}.\left(-\dfrac{7}{5}\right)\)

= \(-\dfrac{7}{5}.\left(15\dfrac{1}{4}-25\dfrac{1}{4}\right)\)

= \(-\dfrac{7}{5}.\left(\dfrac{61}{4}-\dfrac{101}{4}\right)\)

= \(-\dfrac{7}{5}.\left(-10\right)\)

= \(14\)

b) \(38-2y=\dfrac{4}{3}\)

\(2y=38-\dfrac{4}{3}=\dfrac{110}{3}\Rightarrow y=\dfrac{55}{3}\)