Question

Tìm x,y ϵ Q

(x-3) ((2x-1)² -4) = 0

Answer 1

(x-3)[(2x-1)²-4) = 0

<=> \(\left[\begin{array}{nghiempt}x-3=0\\\left[2x-1\right]^2-4=0\end{array}\right.\)

<=> \(\left[\begin{array}{nghiempt}x=3\\\left[2x-1\right]^2=4\end{array}\right.\)

<=> \(\left[\begin{array}{nghiempt}x=3\\\left[\begin{array}{nghiempt}2x-1=2\\2x-1=-2\end{array}\right.\end{array}\right.\)

<=> \(\left[\begin{array}{nghiempt}x=3\\x=\frac{3}{2}\\x=-\frac{1}{2}\end{array}\right.\)

Answer 2

(x-3) ((2x-1)² -4) = 0

=>x-3=0 hoặc (2x-1)² -4= 0

=>x=3 hoặc (2x-1)²=2²

=>x=3 hoặc 2x-1=2 =>2x=3=>x=3/2