Ta có : \(\frac{5}{y}=\frac{3}{x}\)
\(\Rightarrow x=\frac{3y}{5}\)
Thay \(x=\frac{3y}{5}\)vào 2x-3y=7 ta được :
2.\(\frac{3y}{5}-3y=7\)
\(\Rightarrow\frac{6y}{5}-3y=7\)
\(\Rightarrow\frac{6y-15y}{5}=7\)
\(\Rightarrow-9y=35\)
\(\Rightarrow y=-\frac{35}{9}\)
\(\Rightarrow x=\frac{3y}{5}=\frac{3.-\frac{35}{9}}{5}=-\frac{35}{27}\)
Vậy ...