Ta có: \(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}\)
\(\Leftrightarrow\left(1+2y\right).24=\left(1+4y\right).18\)
\(\Rightarrow24+48y=18+72y\)
\(\Rightarrow72y-48y=24-18\)
\(\Rightarrow24y=16\)
\(\Rightarrow y=\dfrac{1}{4}\)
Lại có: \(\dfrac{1+4y}{24}=\dfrac{1+6y}{6x}\)
\(\Rightarrow\dfrac{1+4.\dfrac{1}{4}}{24}=\dfrac{1+6.\dfrac{1}{4}}{6x}\)
\(\Rightarrow\dfrac{1}{12}=\dfrac{\dfrac{5}{2}}{6x}\)
\(\Rightarrow6x.1=12.\dfrac{5}{2}\)
\(\Rightarrow x=5\)
Vậy ta tìm được cặp \(x,y\) là \(x=5\) , \(y=\dfrac{1}{4}\)
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