\(x-2\sqrt{x}=0\) ( đk ; x không âm )
\(\Rightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}\sqrt{x}=0\\\sqrt{x}-2=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x=4\end{array}\right.\)
Vậy x = 0 ; x = 4