Question

Tìm x,bt:

x^2-2x=0

Mn giải giúp e vs ạ

Answer 1

\(x^2-2x=0\)

\(\Leftrightarrow x.\left(x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=0+2=2\end{matrix}\right.\)

Vậy : \(x\in\left\{0,2\right\}\)

Answer 2

=>\(\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)