Giải:
Ta có:
\(\frac{x}{-45}=\frac{-20}{x}\)
\(\Rightarrow x^2=\left(-45\right).\left(-20\right)\)
\(\Rightarrow x^2=900\)
\(\Rightarrow x=30\) hoặc \(x=-30\)
Vậy \(x=30\) hoặc \(x=-30\)
\(\frac{x}{-45}=\frac{-20}{x}\)
=> \(x^2=900\)
=> \(\left[\begin{array}{nghiempt}x=30\\x=-30\end{array}\right.\)
Ta có: x/-45 = -20/x
=> x^2 = -45 . (-20)
=> x^2 = 900
=> x^2 = 30^2 hoặc x^2 = (-30)^2
Vậy x = {-30; 30}
ta suy ra: x*x=-45*-20=900
suy ra x^2=900
x=30
\(\frac{x}{-45}=\frac{-20}{x}\\ \Rightarrow x^2=-45.-20=900\\ \Rightarrow x=\left[\begin{array}{nghiempt}30\\-30\end{array}\right.\)
Vậy x=-30 hoặc 30
