Question

Tìm x,biết:

1) 3\(\dfrac{1}{4}\).x+(\(\dfrac{-7}{6}\)).x-1\(\dfrac{2}{3}\)=\(\dfrac{5}{12}\)

2) \(\dfrac{2}{3}\).x-\(\dfrac{1}{2}\).x =\(\dfrac{5}{12}\)

3) (x+\(\dfrac{1}{5}\))^{2 +\(\dfrac{17}{25}\)=\(\dfrac{26}{25}\)}

⁴⁾ -1\(\dfrac{5}{27}\)-(3x-\(\dfrac{7}{9}\))³=\(\dfrac{-24}{27}\)

Giúp mình nhé mình đang cần gấp

Answer 1

3) \(\left(x+\dfrac{1}{5}\right)^2\) + \(\dfrac{17}{25}\) = \(\dfrac{26}{25}\)

=> \(\left(x+\dfrac{1}{5}\right)^2\) = \(\dfrac{26}{25}\) - \(\dfrac{17}{25}\)

=> \(\left(x+\dfrac{1}{5}\right)^2\) = \(\dfrac{9}{25}\)

=> \(\left(x+\dfrac{1}{5}\right)^2\) = \(\dfrac{3}{5}.\dfrac{3}{5}\)

=> \(\left(x+\dfrac{1}{5}\right)^2\) = \(\left(\dfrac{3}{5}\right)^2\)

=> \(x\) + \(\dfrac{1}{5}\) = \(\dfrac{3}{5}\)

=> \(x\) = \(\dfrac{3}{5}\) - \(\dfrac{1}{5}\)

=> \(x\) = \(\dfrac{2}{5}\)

Answer 2

4) -1\(\dfrac{5}{27}\) - \(\left(3x-\dfrac{7}{9}\right)^3\) = \(\dfrac{-24}{27}\)

=> \(\dfrac{-32}{27}\) - \(\left(3x-\dfrac{7}{9}\right)^3\) = \(\dfrac{-8}{9}\)

=> \(\left(3x-\dfrac{7}{9}\right)^3\) = \(\dfrac{-32}{27}\) - \(\dfrac{-8}{9}\)

=> \(\left(3x-\dfrac{7}{9}\right)^3\) = \(\dfrac{-8}{27}\)

=> \(\left(3x-\dfrac{7}{9}\right)^3\) = \(\dfrac{-2}{3}\) . \(\dfrac{-2}{3}\) . \(\dfrac{-2}{3}\)

=> \(\left(3x-\dfrac{7}{9}\right)^3\) = \(\left(\dfrac{-2}{3}\right)^3\)

=> \(3x-\dfrac{7}{9}=\dfrac{-2}{3}\)

=> \(3x=\dfrac{-2}{3}+\dfrac{7}{9}\)

=> \(3x=\dfrac{1}{9}\)

=> \(x=\dfrac{1}{9}:3\)

=> \(x=\dfrac{1}{27}\)

Answer 3

1) 13/4 .x+ (-7/6).x - 5/3 = 5/12

[13/4 +(-7/6)].x - 5/3 = 5/12

25/12 . x - 5/3 = 5/12

25/12 . x = 5/12 + 5/3

25/12 .x = 25/12

x = 25/12 : 25/12 = 1

Vậy x = 1

2) ( 2/3 - 1/2 ) . x = 5/12

1/6 . x = 5/12

x = 5/12 : 1/6 = 5/2

Vậy x = 5/2

3) (x + 1/5)² = 26/25 - 17/25

(x + 1/5)² = 9/25

(x + 1/5)^{2 =} (3/5)²

x + 1/5 = 3/5

x = 3/5 - 1/5 = 2/5

Vậy x = 2/5

4) Hơi rắc rối xíu

- 32/27 - ( 3x - 7/9)³ = -24/27

( 3x - 7/9 )³ = ( - 32/27 ) - ( - 24/27 )

( 3x - 7/9 )³ = -8/27

( 3x - 7/9 ) ^{3 =} ( 2/3 )³

3x - 7/9 = 2/3

3x= 2/3 + 7/9

3x = 13/9

x = 13/9 : 3 = 13/27

Vậy x= 13/27

Nếu có sai sót gì mong các bạn nhắc nhở để mình xem lại

Answer 4

1) 3\(\dfrac{1}{4}\)x + \(\dfrac{-7}{6}\)x - 1\(\dfrac{2}{3}\) = \(\dfrac{5}{12}\)

<=> \(\dfrac{13}{4}\)x + \(\dfrac{-7}{6}\)x - \(\dfrac{5}{3}\) = \(\dfrac{5}{12}\)

<=> x \(\left(\dfrac{13}{4}+\dfrac{-7}{6}\right)\) - \(\dfrac{5}{3}\) = \(\dfrac{5}{12}\)

<=> x . \(\dfrac{25}{12}\) - \(\dfrac{5}{3}\) = \(\dfrac{5}{12}\)

<=> x . \(\dfrac{25}{12}\) = \(\dfrac{5}{12}\) + \(\dfrac{5}{3}\)

<=> x . \(\dfrac{25}{12}\) = \(\dfrac{25}{12}\)

<=> x = \(\dfrac{25}{12}\) : \(\dfrac{25}{12}\)

<=> x = 1

Answer 5

2) \(\dfrac{2}{3}\)x - \(\dfrac{1}{2}\)x = \(\dfrac{5}{12}\)

=> x \(\left(\dfrac{2}{3}-\dfrac{1}{2}\right)\) = \(\dfrac{5}{12}\)

=> x . \(\dfrac{1}{6}\) = \(\dfrac{5}{12}\)

=> x = \(\dfrac{5}{12}\) : \(\dfrac{1}{6}\)

=> x = \(\dfrac{5}{2}\)

Answer 6

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Answer 7

https://i.imgur.com/SFC660p.gif