Question

Tìm x:

\(|x+2|-6x=1\)

Answer 1

=6x+1(1)

TH1: Nếu x+2 \(\ge\)0 \(\Leftrightarrow\)x\(\ge\)-2 \(\Rightarrow\)|x+2|=x+2

Thay vào (1) ta có:

x+2 = 6x + 1

\(\Leftrightarrow\)x-6x=1-2

\(\Leftrightarrow\)-5x=-1

\(\Leftrightarrow\)x= \(\dfrac{1}{5}\)(TMĐK)

TH2: Nếu x+2\(\le\)0 \(\Leftrightarrow\)x < -2 \(\Rightarrow\)|x+2| = -(x+2)

Thay vào (1) ta có:

-x-2=6x+1

\(\Leftrightarrow\)-x-6x=1+2

\(\Leftrightarrow\)-7x=3

\(\Leftrightarrow\)x=\(-\dfrac{3}{7}\)(KTMĐK)

Vậy S={\(\dfrac{1}{5}\)}