Question

tìm x

\(x-3\sqrt{x}+2=0\)

Answer 1

\(x-3\sqrt{x}+2=0\)

\(\sqrt{x^2}-3\sqrt{x}+2=0\)

\(\sqrt{x}\left(\sqrt{x}-3\right)=-2=1.\left(-2\right)\)

=> \(\sqrt{x}=1\)=> x =1;

Vậy x = 1

Answer 2

ta có \(x-3\sqrt{x}+2=0\)

=> \(x-3\sqrt{x}=-2\)

=> \(\sqrt{x}\left(\sqrt{x}-3\right)=-2=-1\cdot2=-2\cdot1\)

Mà \(\sqrt{x}>=0\) => \(\sqrt{x}=1hoặc\sqrt{x}=2\)

=> x=1 hoặc x=4

Vậy ...