Question

tìm x :\(\left(3x+1\right)^5\)=\(\frac{1}{3}\)               

cảm ơn các bạn đã giúp mình

Answer 1

\(\left(3x+1\right)^5=\frac{1}{32}\)

\(\left(3x+1\right)^5=\left(\frac{1}{2}\right)^5\)

\(3x+1=\frac{1}{2}\)

\(3x=\frac{1}{2}-1\)

\(3x=-\frac{1}{2}\)

\(x=-\frac{1}{2}\div3\)

\(x=-\frac{1}{2}\times\frac{1}{3}\)

\(x=-\frac{1}{6}\)

Answer 2

\(\left(3x+1\right)^5=\left(\frac{1}{2}\right)^5\)
\(\Rightarrow3x+1=\frac{1}{2}\)
\(\Rightarrow3x=\frac{1}{2}-1=\frac{-1}{2}\)
\(\Rightarrow x=\frac{-1}{2}:2=\frac{-1}{6}\)

Answer 3

mình viết sai đề đó là \(\frac{1}{32}\)nha mấy bạn