(x+5).(x+37:34-32.3- 45)=0
\(\Rightarrow\)(x+5).(x+33-33- 45)=0
\(\Rightarrow\)(x+5).(x- 45)=0
\(\Rightarrow\)\(\left[\begin{array}{nghiempt}x+5=0\\x-45=0\end{array}\right.\) \(\left[\begin{array}{nghiempt}x=-5\\x=45\end{array}\right.\)
Vậy x = -5; 45