Question

Tìm x: \(\frac{\frac{1}{2}-\frac{x+2}{3}}{2}-\frac{2}{3}\left(x+1\right)=\frac{1}{4}\left(1-2x\right)-\frac{\frac{1}{3}-\frac{1-x}{2}}{2}\)

Answer 1

<=> \(\frac{-2x-1}{12}\)-\(\frac{2x+2}{3}=\frac{1-2x}{4}-\frac{3x-1}{12}\)

<=>\(\frac{-2x-1-8x-8-3+6x+3x-1}{12}=0\)

<=> -x-13=0=> x=-13

Answer 2

\(\frac{\frac{1}{2}-\frac{x+2}{3}}{2}-\frac{2}{3}\left(x+1\right)=\frac{1}{4}\left(1-2x\right)-\frac{\frac{1}{3}-\frac{1-x}{2}}{2}\)

<=>\(6.\left(\frac{1}{2}-\frac{x+2}{3}\right)-8.\left(x+1\right)=3\left(1-2x\right)-6.\left(\frac{1}{3}-\frac{1-x}{2}\right)\)

<=>3-2.(x+2)-8x-8=3-6x-2+3.(1-x)

<=>3-2x-4-8x-8=3-6x-2+3-3x

<=>-10x-9=-9x+4

<=>x=-13