\(\frac{1}{9}.3^4.3^x=3^7\)
\(3^x=3^5\)
\(x=5\)
1) \(9^{x-1}=9\)
\(\Rightarrow x-1=1\)
\(x=1+1\)
\(x=2\)
Vậy \(x=2\)
2) \(27\div3^x=3\)
\(3^x=27\div3\)
\(3^x=9\)
\(\Rightarrow3^x=3^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
3) \(\frac{1}{9}.3^4.3^x=3^7\)
\(9.3^x=3^7\)
\(\Rightarrow3^2.3^x=3^7\)
\(3^x=3^7\div3^2\)
\(3^x=3^{7-2}\)
\(3^x=3^5\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
27:3X=3=>3X=9=>X=2
TICK CHO MIK NHA