Mình nghĩ đề phải là như này :
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\Leftrightarrow\frac{x+429}{327}+\frac{x+429}{326}+\frac{x+429}{325}+\frac{x+429}{324}+\frac{x+429}{5}=0\)
\(\Leftrightarrow\left(x+429\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
\(\Leftrightarrow x+429=0\Leftrightarrow x=-429\)