Trường hợp 1: x>=1
Pt sẽ là \(x^2-3x+2+x-1=0\)
\(\Leftrightarrow x^2-2x+1=0\)
=>x=1(nhận)
Trường hợp 2: x<1
Pt sẽ là \(x^2-3x+2+1-x=0\)
\(\Leftrightarrow x^2-4x+3=0\)
=>(x-1)(x-3)=0
=>x=1(loại) hoặc x=3(loại)
Tìm x, biết
a) ( x^2 -1/2.x ) :2x + ( 3x - 1 )^2 : ( 1-3x) =0
b) ( x-1)^3 + 1 + 3x( x - 4) = 0
Tìm x, biết.
a/ 3x + 2(5 – x) = 0 b/ x(2x – 1)(x + 5) – (2x2 + 1)(x + 4,5) = 3,5
c/ 3x2 – 3x(x – 2) = 36.
d/ (3x2 – x + 1)(x – 1) + x2(4 – 3x) =
Bài 1: Tính chia:
a) (6x5y2 - 9x4y3 + 15x3y4): 3x3y2 b) (2x3 - 21x2 + 67x - 60): (x - 5) 
c) (6x3 – 7x2 – x + 2) : (2x + 1) d) (x2 – y2 + 6x + 9) : (x + y + 3)
Tìm x biết :
a) \(\left(x-2\right)^3+6\left(x+1\right)^2-x^3+12=0\)
b) \(\left(x-5\right)\left(x+5\right)-\left(x+3\right)^3+3\left(x-2\right)^2=\left(x+1\right)^2-\left(x+4\right)\left(x-4\right)+3x^2\)
c) \(\left(2x+3\right)^2+\left(x-1\right)\left(x+1\right)=5\left(x+2\right)^2-\left(x-5\right)\left(x+1\right)+\left(x+4\right)^2\)
d) \(\left(1-3x\right)^2-\left(x-2\right)\left(9x+1\right)=\left(3x-4\right)\left(3x+4\right)-9\left(x+3\right)^2\)
tìm x, biết
5x (3x-1) + x(3x-1) - 2 (3x-1) =0
2 . ( x³ -1)-2x²(x+2x⁴) +(4x⁵+4)x=6. 3. (X²-4x+16)(x+4)-x(x+1)(x+2)+3x²= 0 4 . ( 8x +2 ) (1-3x) + ( 6x-1)(4x-10) =-50 Đề bài là tìm x nha mn Nhanh giúp mik vs
Tìm x biết
3x(x-1) + 1 - x = 0
25 - x ^2 + 2 x - 1 = 0
( x - 3) tất cả bình phương - ( x+3)(x-1) = 7
tìm x biết
a.3(x-1)2-3x(x-5)-2=0
b.x3-x2-x+1=0
c.2x2-5x-7=0
Tìm x biết:
a)(x+3)^2+(x-2)(x+2)-2(x+1)=7
b)x(2x-1)-(x-2)(2x+3)=0
c)(x-1)(x+2)-x-2=0
d)x[(3x+2)+(x+1)^2-(2x-5)(2x+5)]=0
đ) 2x^2-7x+5=0
e) (2x+3)(x-5)=(2x+1)(2×+3)
19 Tìm x, biết
a) (x+2)(x+3)-(x-2)(x+5)=0 ; b) (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
c) (8-4x)(x+2)+4(x-2)(x+1)=0 ; d) (2x-3)(8x+2)=(4x+1)(4x-1)-3
