Ta có : \(x.\left|x-4\right|=x\) ( vì \(x\ge0\) )
Nếu x = 0 thì \(0.\left|0-4\right|=0\) ( đúng )
Nếu \(x\ne0\) thì ta có \(\left|x-4\right|=1\Leftrightarrow x-a=\pm1\Leftrightarrow\left[{}\begin{matrix}x=5\\x=3.\end{matrix}\right.\)
Vậy x = 0, 5, 3
Ta có : \(x.\left|x-4\right|=x\) ( vì \(x\ge0\) )
Nếu x = 0 thì \(0.\left|0-4\right|=0\) ( đúng )
Nếu \(x\ne0\) thì ta có \(\left|x-4\right|=1\Leftrightarrow x-a=\pm1\Leftrightarrow\left[{}\begin{matrix}x=5\\x=3.\end{matrix}\right.\)
Vậy x = 0, 5, 3
Tìm x biết: \(\left|x-\dfrac{1}{3}\right|\)+\(\dfrac{4}{5}\)\(=\left|-3,2+\dfrac{2}{5}\right|\)
Bài 1,Tìm x,biết:
a, \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b, \(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x-9\right|=5\)
Tìm x, biết:
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
Bài 4 : Tìm x,y biết :
a)\(3\dfrac{1}{4}-\dfrac{1}{4}\left|x-0,25\right|=\dfrac{1}{4}\)
b)\(\left|x-3\right|=-4\)
c)\(\left|x-\dfrac{1}{2}\right|+1=0\)
d)\(\left|x-\dfrac{1}{5}\right|=\left|\dfrac{3}{4}-2x\right|\)
e)\(\left|x+2\right|3=0\)
f)\(\left|2x-1\right|-\left|x+2\right|=0\)
g)\(\left|x+2\right|+\left|y-1\right|=0\)
h)\(\left|2x\right|+\left|y+\dfrac{1}{4}\right|=0\)
Tìm x,y biết :
a ) \(1-\left|x-\dfrac{1}{4}\right|=0,25\)
b)\(\left|x+0,5\right|+2,25=0,5\)
c)\(\left|2x+5\right|=\left|1-x\right|\)
d)\(\left|x-2\right|-0,5=\dfrac{1}{4}\)
e)\(\left|\dfrac{3}{2}-x\right|+2=2\)
f)\(\left|x-3\right|+5=4\)
g)\(\left|\dfrac{1}{2}x-3\right|+\left|y+0,5\right|=0\)
h)\(\left|x+4\right|+\left|1-2y\right|=0\)
giup mình voi mình sap đi học rồi
Tìm \(x\in\mathbb{Q}\), biết :
a) \(\left|x\right|=2,1\)
b) \(\left|x\right|=\dfrac{3}{4},x< 0\)
c) \(\left|x\right|=-1\dfrac{2}{5}\)
d) \(\left|x\right|=0,35,x>0\)
tìm x biết : \(\left|x\right|+\left|-x\right|=4\)
Bài 1: Tìm x biết
a) \(\left|x-\dfrac{1}{3}\right|=2\dfrac{1}{5}\)
b) \(\left|-x+\dfrac{2}{5}\right|+\dfrac{1}{2}=3,5\)
c) \(\left|x+\dfrac{1}{4}\right|-\dfrac{3}{4}=5\%\)
Bài 2: Rút gọn biểu thức sau nếu x < -1,3
A= \(\left|x+1,3\right|-\left|x-2,5\right|\)
B= \(\left|-x-1,3\right|-\left|x-2,5\right|\)
Bài 3: Tìm x biết
a) \(\left|x-1\right|=x-1\)
b) \(\left|x-1\right|=1-x\)
c) \(x-1< \left|x-1\right|\)
d) \(x-1>\left|x-1\right|\)
Tìm \(x\), biết :
\(\left|x+1\right|+\left|x+4\right|=3x\)