Ta có: \(\left(2x-3\right)^2=25\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=5\\2x-3=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=8\\2x=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-1\end{matrix}\right.\)
Ta có: \(\left(2x-3\right)^2=25\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=5\\2x-3=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=8\\2x=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-1\end{matrix}\right.\)
tìm x biết :
a) \(\left|x+\dfrac{1}{2}\right|\)=\(\dfrac{5}{2}\) b) \(\left|2x-\dfrac{2}{3}\right|\)+\(\dfrac{1}{3}\)=0 c) |x-2| = 2x + 1
Tìm \(x\), biết :
a) \(\left(2,8x-32\right):\dfrac{2}{3}=-90\)
b) \(\left(4,5-2x\right):1\dfrac{4}{7}=\dfrac{11}{14}\)
làm đầy đủ theo các bước nhé
Tìm x biết :
a) \(^{\dfrac{4}{9}+x=\dfrac{5}{3}}\)
b)\(\dfrac{3}{4}.x=\dfrac{-1}{2}\)
c) \(\dfrac{3}{7}+\dfrac{5}{7}:x=\dfrac{1}{3}\)
d)\(3\dfrac{1}{4}:\left|2x-\dfrac{5}{12}\right|=\dfrac{39}{16}\)
Tìm số nguyên \(x\), biết rằng :
\(4\dfrac{1}{3}.\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\le x\le\dfrac{2}{3}.\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)
Tìm giá trị lớn nhất của biểu thức:
a) A= 4- |2x + 5| b) B= \(\dfrac{2019}{\left|x-1\right|+5}\) c) C= 4- |x -2| - |3y + 6|
\(\left\{x+\dfrac{1}{5^{ }}^{ }\right\}^2\)+\(\dfrac{17}{25}\)=\(\dfrac{26}{25}\)
GIUP MIK NHA
MIK TICK CHO
Tìm \(x\), biết :
\(\left(\dfrac{1}{12}+3\dfrac{1}{6}-30,75\right)x-8=\left(\dfrac{3}{5}+0,415+\dfrac{1}{200}\right):0,01\)
Tìm các số nguyên x, y biết:
\(^{\left(x^2+1\right)\cdot\left(x+1\right)=3^y}\)
\(H=\dfrac{1}{7}.\left(-0,28\right)+\dfrac{2}{14}.16\%+\left(-3\dfrac{1}{7}\right).\dfrac{1}{25}\)