Ta có: \(\frac{73-x}{98-x}=\frac{1}{6}\)
\(\Rightarrow6\left(73-x\right)=98-x\)
\(\Rightarrow438-6x=98-x\)
\(\Rightarrow438-98=-x+6x\)
\(\Rightarrow340=5x\)
\(\Rightarrow x=340:5=68\)
\(\frac{73-x}{98-x}=\frac{1}{6}\)
=> \(6\left(73-x\right)=98-x\)
=> \(438-6x=98-x\)
\(\Leftrightarrow-6x+x=98-438\)
\(\Leftrightarrow-5x=-340\)
\(\Leftrightarrow x=68\)
Giải:
Ta có: \(\frac{73-x}{98-x}=\frac{1}{6}\)
\(\Rightarrow\left(73-x\right)6=98-x\)
\(\Rightarrow438-6x=98-x\)
\(\Rightarrow6x-x=438-98\)
\(\Rightarrow5x=340\)
\(\Rightarrow x=68\)
Vậy \(x=68\)
