Question

Tím x biết:

\(\dfrac{5}{3}-\dfrac{2}{3}.x=1\)

b) \(\dfrac{4}{5}+\dfrac{5}{7}:x=\dfrac{1}{6}\)

Answer 1

a) \(\dfrac{5}{3}-\dfrac{2}{3}x=1\)

\(\dfrac{2}{3}x=\dfrac{2}{3}\)

\(\Rightarrow x=1\)

Vậy \(x=1\)

b) \(\dfrac{4}{5}+\dfrac{5}{7}:x=\dfrac{1}{6}\)

\(\dfrac{5}{7}:x=-\dfrac{19}{30}\)

\(\Rightarrow x=-\dfrac{150}{133}\)

Vậy \(x=-\dfrac{150}{133}\)

Answer 2

\(\dfrac{5}{3}-\dfrac{2}{3}x=1\)

\(\dfrac{2}{3}x=\dfrac{5}{3}-1\)

\(\dfrac{2}{3}x=\dfrac{2}{3}\)

\(\Rightarrow x=1\)

Answer 3

a) \(\dfrac{5}{3}-\dfrac{2}{3}x=1\)

\(\dfrac{2}{3}x=\dfrac{5}{3}-1\)

\(\dfrac{2}{3}x=\dfrac{5}{3}-\dfrac{3}{3}\)

\(\dfrac{2}{3}x=\dfrac{2}{3}\)

\(x=\dfrac{2}{3}:\dfrac{2}{3}\)

\(x=1\)

Vậy \(x=1\).

b) \(\dfrac{4}{5}+\dfrac{5}{7}:x=\dfrac{1}{6}\)

\(\dfrac{5}{7}:x=\dfrac{1}{6}-\dfrac{4}{5}\)

\(\dfrac{5}{7}:x=\dfrac{5}{30}-\dfrac{24}{30}\)

\(\dfrac{5}{7}:x=-\dfrac{19}{30}\)

\(x=\dfrac{5}{7}:\left(-\dfrac{19}{30}\right)\)

\(x=\dfrac{5}{7}\cdot\left(-\dfrac{30}{19}\right)\)

\(x=-\dfrac{150}{133}\)

Vậy \(x=-\dfrac{150}{133}\).