a, x+7=12
x=12-7
x=5
b, x-15=-21
x=-21+15
x=-6
c, 17-(x-9)=12
x-9=17-12
x-9=5
x=5+9
x=14
d, \(\left|x\right|+\left|-35\right|=41\)
\(\left|x\right|+35=41\)
\(\left|x\right|=41-35\)
\(\left|x\right|=6\)
\(\Rightarrow x=6\) hoặc \(x=-6\)
Vậy \(x\in\left\{6;-6\right\}\)
e, \(\left|x+3\right|=6\)
=> x+3=6 hoặc x+3=-6
+) x+3=6
x=6-3
x=3
+) x+3=-6
x=(-6)-3
x=-3
f, \(\left|-11\right|-\left|2-x\right|=9\)
\(11-\left|2-x\right|=9\)
\(\left|2-x\right|=11-9\)
\(\left|2-x\right|=2\)
\(\Rightarrow2-x=2\) hoặc \(2-x=-2\)
+) 2-x=2
x=2-2=0
+) 2-x=-2
x=2-(-2)=4