\(\left(x-2\right)^2-\left(x+3\right)^2-4\left(x+1\right)=5\Rightarrow x^2-4x+4-x^2-6x-9-4x-4=5\Rightarrow-14x=14\Rightarrow x=-1\)
\(\Rightarrow\left[\left(x-2\right)^2-\left(x+3\right)^2\right]-4\left(x+1\right)\)=5
\(\Rightarrow\left(x-2-x-3\right)\left(x-2+x+3\right)-4x-4=5\)
\(\Rightarrow-5.\left(2x+1\right)-4x-4=5\)
\(\Rightarrow-10x-5-4x-4=5\)
\(\Rightarrow-14x-9=5\Rightarrow-14x=14\Rightarrow x=-1\)
\(\Leftrightarrow\) x2-2.x.2+22 - (x2+2.x.3+32)- 4x-4=5
\(\Leftrightarrow\) x2-4x+4-x2-6x-9-4x-4-5=0
\(\Leftrightarrow\) -14x-14=0
\(\Leftrightarrow\)-14x =14
\(\Leftrightarrow\) x=-1
Ta có: \(\left(x-2\right)^2-\left(x+3\right)^2-4\left(x+1\right)=5\)
\(\Leftrightarrow x^2-4x+4-x^2-6x-9-4x-4=5\)
\(\Leftrightarrow-14x=10\)
hay \(x=-\dfrac{5}{7}\)
