\(\frac{3-x}{5-x}=\left(\frac{3}{5}\right)^2=\frac{9}{25}\)
=> (3 - x). 25 = (5 - x). 9
=> 75 - 25x = 45 - 9x
=> 45 - 75 = 9x - 25x
=> -30 = -16x
=> x = \(\frac{-30}{-16}=\frac{15}{8}\)
\(\frac{3-x}{5-x}=\left(\frac{3}{5}\right)^2\)
\(\frac{3-x}{5-x}=\frac{9}{25}\)
\(25\times\left(3-x\right)=9\times\left(5-x\right)\)
\(75-25x=45-9x\)
\(25x-9x=75-45\)
\(16x=30\)
\(x=\frac{30}{16}\)
\(x=\frac{15}{8}\)
\(\frac{3-x}{5-x}=\left(\frac{3}{5}\right)^2\)
\(\Rightarrow\frac{3-x}{5-x}=\frac{9}{25}\)
\(\Rightarrow\left(3-x\right).25=\left(5-x\right).9\)
\(\Rightarrow75-25x=45-9x\)
\(\Rightarrow25x-9x=75-45\)
\(\Rightarrow x\left(25-9\right)=30\)
\(\Rightarrow16x=30\)
\(\Rightarrow x=30:16\)
\(\Rightarrow x=\frac{15}{8}\)
Vậy \(x=\frac{15}{8}\)
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