ta có: \(\dfrac{x}{3}\) > \(1-\dfrac{2}{3}\) và \(\dfrac{x}{3}\) < \(3\dfrac{1}{3}\)
\(\dfrac{x}{3}\)>\(1-\dfrac{2}{3}\) => \(\dfrac{x}{3}\)>\(\dfrac{1}{3}\) => x>1
\(\dfrac{x}{3}\)<\(3\dfrac{1}{3}\) => \(\dfrac{x}{3}\)<\(\dfrac{10}{3}\) => x<10
=> S= {x|1<x<10}
1-\(\dfrac{2}{3}\)<\(\dfrac{x}{3}\)< \(3\dfrac{1}{3}\)
⇒ \(\dfrac{1}{3}\)< \(\dfrac{x}{3}\)< \(\dfrac{10}{3}\)
⇒ 1 < x < 10
⇒ x ∈ { 2 ; 3 ; 4 ; 5 ; 6 ; 7 ; 8 ; 9 }