Question

Câu 1:Tìm xEN biết

\(\dfrac{1}{5}+\dfrac{2}{30}+\dfrac{121}{165}\le x\le\dfrac{1}{2}+\dfrac{156}{72}+\dfrac{1}{3}\)

Câu 2:Tìm x để biểu thức sau có giá trị là số tự nhiên

\(N=\dfrac{2a+9}{a+3}+\dfrac{5a+17}{a+3}+\dfrac{-3a}{a+3}+\dfrac{-4a-23}{a+3}\)

Answer 1

\(1)\dfrac{1}{5}+\dfrac{2}{30}+\dfrac{121}{156}\le x\le\dfrac{1}{2}+\dfrac{156}{72}+\dfrac{1}{3}\)

\(\dfrac{156}{780}+\dfrac{26}{780}+\dfrac{605}{780}\le x\le\dfrac{3}{6}+\dfrac{13}{6}+\dfrac{2}{6}\)

\(\dfrac{787}{780}\le x\le2\)

\(\Rightarrow x\in\left\{2\right\}\)

Answer 2

Câu 2: 

\(N=\dfrac{2a+9+5a+17-3a-4a-23}{a+3}=\dfrac{3}{a+3}\)

Để N là số tự nhiên thì \(\left\{{}\begin{matrix}a>-3\\a+3\in\left\{1;-1;3;-3\right\}\end{matrix}\right.\Leftrightarrow a\in\left\{-2;0\right\}\)