Question

Tìm x : 

a) x(x - 4 ) - ( x^2 - 8 ) = 0

Answer 1

\(x\left(x-4\right)-\left(x^2-8\right)=0\)

\(\Leftrightarrow x^2-4x-\left(x^2-8\right)=0\)

\(\Leftrightarrow x^2-4x-x^2+8=0\)

\(\Leftrightarrow-4x+8=0\)

\(\Leftrightarrow-4x=-8\)

\(\Leftrightarrow x=-8:-4\)

\(\Leftrightarrow x=2\)

Answer 2

a)\(x\left(x-4\right)-\left(x^2-8\right)=0\)

    \(x^2-4x-x^2+8=0\)

    \(-4x+8=0\)

    \(-4x=-8\)

    \(x=2\)

Vậy \(x=2\)

Answer 3

Ta có:

x.(x-4)-(x²-8)=0

=>x.(x-4)=x²-8

=>x²-4x=x²-8

=>x²-4x-x²=-8

=>-4x=-8

=>x=2

Vậy x=2.

Answer 4

tick nha