\(5x^3=\left(x-1\right)^3\Leftrightarrow\left(\sqrt[3]{5}x\right)^3=\left(x-1\right)^3\Leftrightarrow\sqrt[3]{5}x=x-1\Leftrightarrow x=\dfrac{1}{1-\sqrt[3]{5}}\)
\(\dfrac{a-1}{\sqrt[3]{a^2}+\sqrt[3]{a}+1}=\dfrac{\left(\sqrt[3]{a}\right)^3-1^3}{\sqrt[3]{a^2}+\sqrt[3]{a}+1}=\dfrac{\left(\sqrt[3]{a}-1\right)\left(\sqrt[3]{a^2}+\sqrt[3]{a}+1\right)}{\sqrt[3]{a^2}+\sqrt[3]{a}+1}=\sqrt[3]{a}-1\)