3x-\(\left|2x+1\right|\)=2
\(\Rightarrow\)\(\left|2x+1\right|\)=2+3x (*)
ĐK: 2+3x\(\ge\)0 (**)
từ (*) \(\Leftrightarrow\)\(\left\{\begin{matrix}2x+1=2+3x\\2x+1=-2-3x\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}2x-3x=2-1\\2x+3x=-2-1\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left\{\begin{matrix}-x=1\\5x=-3\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}x=-1\left(loai\right)\\x=\frac{-3}{5}\left(TM\right)\end{matrix}\right.\)
từ (**) Vậy x=\(\frac{-3}{5}\)
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