3-\(\left|x-3\right|\) = 9-3x
(=) \(\left|x-3\right|\) = 3-9-3x
(=) \(\left[{}\begin{matrix}x-3=3-9-3x\\x-3=-3+9+3x\end{matrix}\right.\)
(=) \(\left[{}\begin{matrix}x+3x=3-9+3\\x-3x=-3+9+3\end{matrix}\right.\)
(=) \(\left[{}\begin{matrix}4x=-3\\-2x=9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-3}{4}\\x=\dfrac{-9}{2}=-4,5\end{matrix}\right.\)
1, Tìm x biết
a, ( 4/5 )^2x+5 = 625/256
b, ( 3x - 4 )^4 = ( 3x - 4 )^2
c, 3^x+1 = 9^x
d, 2^2x+3 = 4^x-5
tìm x biết
a) ( 2x+3)^2=9/121
b) (3x-1)^3= -8/27
Tìm x,biết:
a)(3x-1).(2x+7)-(x+1).(6x- 5)=16
b)(10x+9).x-(5x-1).(2x+3)=8
c)(3x- 5).(7- 5x)+(5x+2).(3x-2)-2=0
Rút gọn C = \(\frac{x}{x-3}-\frac{x^2+3x}{2x+3}.\left(\frac{x+3}{x^2-3x}-\frac{x}{x^2-9}\right)\)
Tìm x, bik
a, /x+\(2\frac{1}{3}\) / = 5\(\frac{2}{3}\)
b//3x -2/ +4x = 9
Tìm x thỏa mãn:
a) \(2\left|\frac{2}{3}-x\right|+\frac{1}{4}=\frac{3}{4}\)
b) \(8\sqrt{x}+2x-9=5x+7+6\sqrt{x}-3x-12\)
c) \(2x^2+5x+8+\sqrt{x}=x^2+3x+35+x^2+2x-7\)
tìm x,y,z
\(\frac{x-1}{5}=\frac{y-2}{3}=\frac{z-2}{2}\)và 3x-5y+6z=9
Tìm x , biết :
a ) / 2x - 1 / + / 3x - 4 / = 5
b ) / 3x - 2 / + 4x = 9
c ) / 2x +\(\frac{4}{5}\)/ = / x - \(\frac{3}{2}\)/
1. Tìm x, biết rằng:
a) \(\frac{x+4}{x+3}\) = \(\frac{x+9}{x+4}\)
b) \(\frac{x-5}{x+3}\) = \(\frac{x-4}{x+6}\)
c) \(\frac{3x-1}{3x}\) = \(\frac{2x-1}{2x+1}\)
2. Tìm hai số x và y, biết:
\(\begin{cases}5x+4y=110\\x:y=2:3\end{cases}\)
