\(2-\dfrac{3}{2}x-\dfrac{1}{4}=-\dfrac{5}{4}\)
\(\Rightarrow-\dfrac{3}{4}x=-\dfrac{5}{4}+\dfrac{1}{4}-2\)
\(\Rightarrow-\dfrac{3}{4}x=-3\Rightarrow x=4\)
Chúc bạn học tốt!!!
\(2-\dfrac{3}{2}x-\dfrac{1}{4}=-\dfrac{5}{4}\)
\(\Rightarrow-\dfrac{3}{4}x=-\dfrac{5}{4}+\dfrac{1}{4}-2\)
\(\Rightarrow-\dfrac{3}{4}x=-3\Rightarrow x=4\)
Chúc bạn học tốt!!!
tim x biet |2x+3|-2|4-x|=5
Tim x biet
x-4/3=x+2/-2
2x-1/x-3=2x+3/x-1
tim x , y :
/ 2x - 5 / + / 3x + 1 / = 6
/ x - 4 / + / x - 6 / = 2
/ x- 2 / + / x - 7 / = 4
tim
\(\dfrac{31-2x}{x+23}=\dfrac{9}{4}\),a
b,\(\dfrac{\left|2x-1\right|}{\dfrac{1}{2}}=\dfrac{18}{5}\)
c, \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
d, \(\dfrac{3x+2}{5x-3}=\dfrac{3x-1}{5x-3}\)
tim x
|x-4/5|=3/4
6-|1/2-x|=2/5
|x+3/5|-1/2=1/2
làm giúp mình với
bai 1: cho cac da thuc
f(x)= x^5-3x^2+7x^4-x^5+2x^2-9x^3+x^2-1/4x+2x-3
g(x)=5x^4-x^5+1/2x^4+x^5+x^2-4x^4-2x^3+3x^2+x^3-1/4
a, thu gon va sap xep cac da thuc tren theo luy thua giam dancua ien
b,tinh f(1);f(-1); g(1); g(-1)
c,tinh f(x)+g(x);f(x)-g(x)
1, Tìm x biết
a, ( 4/5 )^2x+5 = 625/256
b, ( 3x - 4 )^4 = ( 3x - 4 )^2
c, 3^x+1 = 9^x
d, 2^2x+3 = 4^x-5
tim GTLN: D=-3-/2x+4/
tìm GTNN:A=3*/1-2x/-5
TIm x y z
2x/3 = 3y/4 = 4z/5 va x + y + z = 49