\(\frac{2n+2}{n-1}=\frac{2\left(n-1\right)+4}{n-1}=2+\frac{4}{n-1}\)
Vì \(n\in Z\Rightarrow n-1\in Z\)
\(\Rightarrow P\in Z\) khi \(4⋮n-1\Rightarrow n-1\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)
Bảng
n-1 | 1 | -1 | 2 | -2 | 4 | -4 |
n | 2 | 0 | 3 | -1 | 5 | -3 |