Lời giải:
Ta có:
\(2x^7=3x^5\Leftrightarrow 2x^7-3x^5=0\)
\(\Leftrightarrow x^5(2x^2-3)=0\)
\(\Rightarrow \left[\begin{matrix} x^5=0\\ 2x^2-3=0\end{matrix}\right.\Rightarrow \left[\begin{matrix} x=0\\ x^2=\frac{3}{2}\end{matrix}\right.\Rightarrow \left[\begin{matrix} x=0\\ x=\sqrt{\frac{3}{2}}\\ x=-\sqrt{\frac{3}{2}}\end{matrix}\right.\)