\(x^5=x\)
\(\Rightarrow x^5-x=0\)
\(\Rightarrow x\left(x^4-1\right)=0\)
\(\Rightarrow x=0\) hoặc \(x^4-1=0\)
+) \(x=0\)
+) \(x^4-1=0\)
\(\Rightarrow x^4=1\)
\(\Rightarrow x=1\) hoặc \(x=-1\)
Vậy \(x\in\left\{0;1;-1\right\}\)
\(x^5=x\)
\(\Rightarrow x\in\left\{0;1\right\}\)
Vậy \(x\in\left\{0;1\right\}\)
\(x^5=x\)
\(\Rightarrow x^5-x=0\)
\(x.x^4-x.1=0\)
\(\Rightarrow x\left(x^4-1\right)=0\)
\(\Rightarrow x=0\) hoặc \(x^4-1=0\)
\(\Rightarrow x=0\) hoặc \(x^4=1\)
\(\Rightarrow x=0\) hoặc \(x^4=1^4\)
\(\Rightarrow x\in\left\{0;1\right\}\)
Vậy : \(x\in\left\{0;1\right\}\)
Vi chi co1 la luy thua voi so nao cung bang chinh no nen x chi co the bang1