x-2=0:5
x-2=0
x=2
(5-x)(x+7)=0
5-x=0 hoặc x+7=0
x=5 hoặc x=-7
(-4)x=20
x=20:(-4)
x=-5
a)\(5\left(x-2\right)=0\)
\(\Rightarrow x-2=0\)
\(\Rightarrow x=2\)
b) \(\left(5-x\right)\left(x+7\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}5-x=0\\x+7=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=-7\end{matrix}\right.\)
Vậy........
c)\(-4x=20\Rightarrow x=\frac{20}{-4}=-5\)